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Question
solve 3ax + 4ax = 5ax + 4 for x. assume a ≠ 0. a. x = 3a b. x = 2a c. $x = \frac{2}{a}$ d. $x = \frac{1}{3a}$
Step1: Combine like terms left side
$3ax + 4ax = 7ax$
Step2: Subtract $5ax$ from both sides
$7ax - 5ax = 4$
$2ax = 4$
Step3: Solve for x (divide by $2a$)
$x = \frac{4}{2a} = \frac{2}{a}$
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C. $x = \frac{2}{a}$