QUESTION IMAGE
Question
solve for x.
(3x - 11)°
(2x + 16)°
x =
submit
work it out
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transversals of parallel lines: find angle measures (81)
solve linear eq
lesson: transversals of parallel lines
Step1: Identify angle - relationship
The angles $(3x - 11)^{\circ}$ and $(2x + 16)^{\circ}$ are vertical angles, so they are equal.
$3x-11 = 2x + 16$
Step2: Solve the equation for x
Subtract $2x$ from both sides:
$3x-2x-11=2x - 2x+16$
$x - 11=16$
Then add 11 to both sides:
$x-11 + 11=16 + 11$
$x=27$
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$27$