Question

solve.
3y(y + 2)(y + 8) = 0
(if there is more than one solution, separate them with commas.)
y =

Explanation:

Step1: Apply zero product rule

Set each factor to 0:
$3y=0$, $y+2=0$, $y+8=0$

Step2: Solve for y in each equation

For $3y=0$: $\frac{3y}{3}=\frac{0}{3}$ → $y=0$
For $y+2=0$: $y=0-2$ → $y=-2$
For $y+8=0$: $y=0-8$ → $y=-8$

Answer:

$0, -2, -8$