Question

solve for x.
(5x - 30)°
(3x)°
work it out
not feeling ready yet? these can he
transversals of parallel lines: find angle measures (81)
solve linear
lesson: transversals of parallel lines

Explanation:

Step1: Identify angle - relationship

Since \(LM\parallel NO\) and \(JK\) is a transversal, the angles \((5x - 30)^{\circ}\) and \((3x)^{\circ}\) are corresponding angles. Corresponding angles formed by a transversal intersecting two parallel lines are equal. So, \(5x-30 = 3x\).

Step2: Solve the equation for \(x\)

Subtract \(3x\) from both sides: \(5x-3x - 30=3x - 3x\), which simplifies to \(2x-30 = 0\). Then add 30 to both sides: \(2x-30 + 30=0 + 30\), getting \(2x=30\). Divide both sides by 2: \(\frac{2x}{2}=\frac{30}{2}\), so \(x = 15\).

Answer:

\(15\)