Question

solve for x.
n o
(6x + 32)°
p q
(72 - 2x)°
x =
submit

Explanation:

Step1: Identify angle - relationship

Assume \(NO\parallel PQ\), then \((6x + 32)^{\circ}\) and \((72-2x)^{\circ}\) are corresponding angles (or alternate - exterior angles if the lines are parallel), and they are equal. So we set up the equation \(6x + 32=72 - 2x\).

Step2: Solve the equation for \(x\)

Add \(2x\) to both sides of the equation: \(6x+2x + 32=72-2x + 2x\), which simplifies to \(8x+32 = 72\).

Step3: Isolate the term with \(x\)

Subtract 32 from both sides: \(8x+32 - 32=72 - 32\), getting \(8x=40\).

Step4: Solve for \(x\)

Divide both sides by 8: \(x=\frac{40}{8}=5\).

Answer:

\(5\)