Question

solve for all values of x by factoring.\\(x^2 + 3x - 35 = 3x + 1\\)

Explanation:

Step1: Simplify the equation

Subtract $3x + 1$ from both sides:
$x^2 + 3x - 35 - (3x + 1) = 0$
$x^2 - 36 = 0$

Step2: Factor the quadratic

Recognize difference of squares:
$x^2 - 6^2 = 0$
$(x - 6)(x + 6) = 0$

Step3: Solve for x

Set each factor equal to 0:
$x - 6 = 0$ or $x + 6 = 0$

Answer:

$x = 6$ or $x = -6$