Question

solve the equation $9m^5 = 27m^3$. the solutions are $m = \square$, $m = \square$, and $m = \square$.

Explanation:

Step1: Rearrange equation to zero

$9m^5 - 27m^3 = 0$

Step2: Factor out common term

$9m^3(m^2 - 3) = 0$

Step3: Set first factor to zero

$9m^3 = 0 \implies m^3 = 0 \implies m = 0$

Step4: Set second factor to zero

$m^2 - 3 = 0 \implies m^2 = 3 \implies m = \pm\sqrt{3}$

Answer:

$m = 0$, $m = \sqrt{3}$, and $m = -\sqrt{3}$