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solve for c. first, complete the equation. $c^{2}=a^{2}+b^{2}-2ab\\cos …

Question

solve for c.
first, complete the equation.
$c^{2}=a^{2}+b^{2}-2ab\cos c$
$c^{2}=3^{2}+10^{2}-2(3)(10)\cos?$
enter the angle that belongs in the green box.

Explanation:

Step1: Identify the angle for cosine

In the Law - of - Cosines formula $c^{2}=a^{2}+b^{2}-2ab\cos C$, the angle $C$ is the angle opposite to the side $c$. Here, the side opposite to side $c$ is the angle given as $34^{\circ}$. So the angle in the cosine function is $34^{\circ}$.

Answer:

$34^{\circ}$