Question

solve the following inequality for r. write your answer in simplest form.
$-8r + 6 < 3r + 3$

Explanation:

Step1: Subtract $3r$ from both sides

$-8r - 3r + 6 < 3$
$\implies -11r + 6 < 3$

Step2: Subtract 6 from both sides

$-11r < 3 - 6$
$\implies -11r < -3$

Step3: Divide by -11, reverse inequality

$r > \frac{-3}{-11}$
$\implies r > \frac{3}{11}$

Answer:

$r > \frac{3}{11}$