Question

solve $n = \frac{9}{8}p + 29$ for $p$.

the formula, $n = \frac{9}{8}p + 29$, when solved for $p$ changes to $p = \square$.
(simplify your answer.)

Explanation:

Step1: Subtract 29 from both sides

To isolate the term with \( P \), we subtract 29 from both sides of the equation \( N=\frac{9}{8}P + 29 \). This gives us \( N-29=\frac{9}{8}P \).

Step2: Multiply both sides by \( \frac{8}{9} \)

To solve for \( P \), we multiply both sides of the equation \( N - 29=\frac{9}{8}P \) by the reciprocal of \( \frac{9}{8} \), which is \( \frac{8}{9} \). So we have \( P=\frac{8}{9}(N - 29) \). We can also distribute the \( \frac{8}{9} \) to get \( P=\frac{8}{9}N-\frac{232}{9} \).

Answer:

\( \frac{8}{9}(N - 29) \) (or \( \frac{8}{9}N-\frac{232}{9} \))