Question

solve and graph the following inequality: 6 ≥ -3 - 8x

Explanation:

Step1: Add 3 to both sides

$6 + 3\geq-3 - 8x+3$
$9\geq - 8x$

Step2: Divide both sides by -8 and reverse the inequality sign

$\frac{9}{-8}\leq\frac{-8x}{-8}$
$x\geq-\frac{9}{8}$

Answer:

$x\geq-\frac{9}{8}$
To graph: On a number - line, put a closed circle at $-\frac{9}{8}=-1.125$ and shade to the right.