Question

solve $d \cdot (-4) = 32$.
$d = \underline{\quad\quad}$
(lesson 5 - 15)

Explanation:

Step1: Divide both sides by -4

To solve for \( d \) in the equation \( d \cdot (-4) = 32 \), we divide both sides of the equation by \(-4\). This is because the inverse operation of multiplication is division, and we want to isolate \( d \). So we have:
\[
\frac{d \cdot (-4)}{-4} = \frac{32}{-4}
\]

Step2: Simplify both sides

Simplifying the left side, the \(-4\) in the numerator and denominator cancels out, leaving \( d \). For the right side, we calculate \( \frac{32}{-4} \), which is \(-8\) because a positive divided by a negative is a negative, and \( 32 \div 4 = 8 \). So we get:
\[
d = -8
\]

Answer:

\( d = -8 \)