Question

solve the quadratic equation by using the square root property: $x^2 - 2 = 5$

a. $x = \sqrt{7}, x = -\sqrt{7}$

b. $x = \sqrt{3}, x = -\sqrt{3}$

c. $x = \sqrt{7}$

d. $x = -\sqrt{7}$

Explanation:

Step1: Isolate the squared term

Add 2 to both sides to get $x^2$ alone.
$x^2 - 2 + 2 = 5 + 2$
$x^2 = 7$

Step2: Apply square root property

Take square root of both sides, include $\pm$.
$x = \pm\sqrt{7}$

Answer:

A. $x = \sqrt{7}, x = -\sqrt{7}$