Question

solve the system of equations.
$-9y + 4x - 20 = 0$
$-7y + 16x - 80 = 0$
$x = square$
$y = square$
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Explanation:

Step1: Rewrite equations in standard form

$4x - 9y = 20$
$16x - 7y = 80$

Step2: Eliminate $x$ via multiplication

Multiply first equation by 4: $16x - 36y = 80$
Subtract from second equation:
$$(16x - 7y) - (16x - 36y) = 80 - 80$$
$$29y = 0$$

Step3: Solve for $y$

$y = \frac{0}{29} = 0$

Step4: Substitute $y=0$ to find $x$

Substitute into $4x - 9y = 20$:
$4x - 9(0) = 20$
$4x = 20$
$x = \frac{20}{4} = 5$

Answer:

$x = 5$
$y = 0$