QUESTION IMAGE
Question
4 solve the system of equations by substitution:
$x = -2$
$3x - 2y = -18$
Step1: Substitute $x=-2$ into the second equation
$3(-2) - 2y = -18$
Step2: Simplify the left-hand side
$-6 - 2y = -18$
Step3: Isolate the term with $y$
$-2y = -18 + 6$
$-2y = -12$
Step4: Solve for $y$
$y = \frac{-12}{-2}$
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$x=-2$, $y=6$