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Question
solve the system by substitution.
y = -x
y = -5x + 40
Step1: Substitute \( y = -x \) into \( y = -5x + 40 \)
Since both equations are solved for \( y \), we can set them equal to each other. So substitute \( -x \) for \( y \) in the second equation:
\( -x = -5x + 40 \)
Step2: Solve for \( x \)
Add \( 5x \) to both sides of the equation:
\( -x + 5x = -5x + 5x + 40 \)
\( 4x = 40 \)
Divide both sides by 4:
\( x = \frac{40}{4} = 10 \)
Step3: Solve for \( y \)
Substitute \( x = 10 \) into \( y = -x \):
\( y = -10 \)
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The solution to the system is \( x = 10 \), \( y = -10 \) or the ordered pair \( (10, -10) \)