Question

1 solve these problems. if your answer is an improper fraction, find its equivalent mixed number. show your thinking. ex $\frac{3}{4}+\frac{1}{2}=\frac{3}{4}+\frac{2}{4}=\frac{5}{4}=1\frac{1}{4}$ a $1\frac{5}{10}-\frac{4}{10}=$ b $\frac{7}{4}-\frac{3}{4}=$ c $\frac{4}{12}+1\frac{2}{3}=$

Explanation:

Step1: Convert mixed - number to improper fraction for a

Convert $1\frac{5}{10}$ to an improper fraction. $1\frac{5}{10}=\frac{1\times10 + 5}{10}=\frac{15}{10}$. Then $\frac{15}{10}-\frac{4}{10}=\frac{15 - 4}{10}=\frac{11}{10}=1\frac{1}{10}$.

Step2: Subtract fractions for b

Since the denominators are the same, $\frac{7}{4}-\frac{3}{4}=\frac{7 - 3}{4}=\frac{4}{4}=1$.

Step3: Convert mixed - number to improper fraction and find common denominator for c

Convert $1\frac{2}{3}$ to an improper fraction: $1\frac{2}{3}=\frac{1\times3+2}{3}=\frac{5}{3}$. The common denominator of 12 and 3 is 12. $\frac{5}{3}=\frac{5\times4}{3\times4}=\frac{20}{12}$. Then $\frac{4}{12}+\frac{20}{12}=\frac{4 + 20}{12}=\frac{24}{12}=2$.

Answer:

a. $1\frac{1}{10}$
b. $1$
c. $2$