Question

solve using elimination.
$x + 3y = -3$
$-3x - 5y = 13$
$(square, square)$
submit

Explanation:

Step1: Eliminate x variable

Multiply first equation by 3:
$$3(x + 3y) = 3(-3) \implies 3x + 9y = -9$$

Step2: Add to second equation

Add new equation to $-3x -5y=13$:
$$(3x + 9y) + (-3x - 5y) = -9 + 13$$
$$4y = 4$$

Step3: Solve for y

Divide both sides by 4:
$$y = \frac{4}{4} = 1$$

Step4: Substitute y into first equation

Plug $y=1$ into $x + 3y = -3$:
$$x + 3(1) = -3$$

Step5: Solve for x

Isolate x:
$$x = -3 - 3 = -6$$

Answer:

$(-6, 1)$