QUESTION IMAGE
Question
solving with squared and cubed
name:
find the positive value of x.
- $x^2 = 4$ 2) $x^2 = 9$ 3) $x^3 = 125$
- $x^2 = 144$ 5) $x^2 = 49$ 6) $x^3 = 64$
- $x^2 = 81$ 8) $x^2 = 25$ 9) $x^3 = 1$
- $x^3 = 1,000$ 11) $x^3 = 8$ 12) $x^3 = 512$
- $x^2 = 64$ 14) $x^3 = 343$ 15) $x^3 = 216$
- $x^2 = 121$ 17) $x^2 = 100$ 18) $x^3 = 729$
- $x^2 = 36$ 20) $x^2 = 16$ 21) $x^3 = 27$
Step1: Take positive square root
For equations of the form $x^2 = a$, $x = \sqrt{a}$
Step2: Take positive cube root
For equations of the form $x^3 = a$, $x = \sqrt[3]{a}$
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- $x = \sqrt{4} = 2$
- $x = \sqrt{9} = 3$
- $x = \sqrt[3]{125} = 5$
- $x = \sqrt{144} = 12$
- $x = \sqrt{49} = 7$
- $x = \sqrt[3]{64} = 4$
- $x = \sqrt{81} = 9$
- $x = \sqrt{25} = 5$
- $x = \sqrt[3]{1} = 1$
- $x = \sqrt[3]{1000} = 10$
- $x = \sqrt[3]{8} = 2$
- $x = \sqrt[3]{512} = 8$
- $x = \sqrt{64} = 8$
- $x = \sqrt[3]{343} = 7$
- $x = \sqrt[3]{216} = 6$
- $x = \sqrt{121} = 11$
- $x = \sqrt{100} = 10$
- $x = \sqrt[3]{729} = 9$
- $x = \sqrt{36} = 6$
- $x = \sqrt{16} = 4$
- $x = \sqrt[3]{27} = 3$