Question

square pqrs with vertices p(2, 6), q(6, 5), r(5, 1), and s(1, 2): 180°
p( )
q( )
r( , )
s( , )
what are the new vertices for this triangle pqrs, when rotated at 180 degree using rule (-x, -y).

Explanation:

Step1: Apply rule to point P

Given $P(2,6)$, using the rule $(-x,-y)$, we get $P'(-2,-6)$.

Step2: Apply rule to point Q

Given $Q(6,5)$, using the rule $(-x,-y)$, we get $Q'(-6,-5)$.

Step3: Apply rule to point R

Given $R(5,1)$, using the rule $(-x,-y)$, we get $R'(-5,-1)$.

Step4: Apply rule to point S

Given $S(1,2)$, using the rule $(-x,-y)$, we get $S'(-1,-2)$.

Answer:

$P'(-2,-6)$
$Q'(-6,-5)$
$R'(-5,-1)$
$S'(-1,-2)$