Question

standard form to slope-intercept form
date
period
write the slope - intercept form of the equation of each line.
1)

1. 10x - y = 5
2. x + 6y = 24
3. 2x - 3y = -15
4. x + 4y = 4
5. 7x + 2y = 24
6. 3x - 2y = 4
7. 3x + 7y = 35
8. 7x - 2y = 2

a) $y = \frac{7}{2}x - 1$ b) $y = x - \frac{7}{2}$
c) $y = -x - \frac{7}{2}$ d) $y = -\frac{7}{2}x - 1$

1. 8x - 3y = 18

a) $y = -\frac{4}{3}x - 6$ b) $y = \frac{4}{3}x - 6$
c) $y = \frac{2}{3}x - 6$ d) $y = \frac{8}{3}x - 6$

Explanation:

Problem 1: \(8x + y = -2\) (assuming the first problem is \(8x + y = -2\) from the handwriting)

Step1: Isolate \(y\)

Subtract \(8x\) from both sides: \(y = -8x - 2\)

Step1: Isolate \(y\)

Subtract \(10x\) from both sides: \(-y = -10x + 5\)

Step2: Multiply by -1

\(y = 10x - 5\)

Step1: Isolate \(6y\)

Subtract \(x\) from both sides: \(6y = -x + 24\)

Step2: Divide by 6

\(y = -\frac{1}{6}x + 4\)

Answer:

\(y = -8x - 2\)

Problem 2: \(10x - y = 5\)