Question

subtract 12x from both sides and rewrite the equation to represent the values that remain.
20x = 12x + 16
-12x -12x
\boxed{} = \boxed{}

Explanation:

Step1: Subtract 12x from left side

The left side of the equation is \(20x\). Subtract \(12x\) from it: \(20x - 12x\)

Step2: Subtract 12x from right side

The right side of the equation is \(12x + 16\). Subtract \(12x\) from it: \((12x + 16)- 12x = 16\) (simplify by combining like terms \(12x-12x = 0\))

Answer:

The first box (left side result) is \(20x - 12x = 8x\) (wait, actually when we do \(20x-12x\) that's \(8x\), but let's re - check the steps. Wait, the problem is to subtract \(12x\) from both sides. So left side: \(20x-12x\), right side: \((12x + 16)-12x=16\). So the first box is \(20x - 12x=8x\) (but maybe I misread the original equation. Wait the original equation is \(20x=12x + 16\). Then subtract \(12x\) from both sides: \(20x-12x=(12x + 16)-12x\). Then \(20x-12x = 8x\) and \((12x + 16)-12x=16\). So the top box (left side after subtraction) is \(8x\) and the bottom box (right side after subtraction) is \(16\). Wait, but let's do it step by step:

1. Start with \(20x=12x + 16\)
2. Subtract \(12x\) from both sides:

• Left side: \(20x-12x\)
• Right side: \((12x + 16)-12x\)

1. Simplify left side: \(20x-12x = 8x\)
2. Simplify right side: \(12x-12x+16=16\)

So the first (top) box is \(8x\) and the second (bottom) box is \(16\).