Question

svlc algebra 1a - standard (15260)
representing relationships
x | f(x)
-4 | 0
-2 | 2
0 | 8
2 | 2
4 | 0
6 | -2
what are all of the x-intercepts of the continuous function in the table?
option 1: (-4, 0), (4, 0)
option 2: (-4, 0), (0, 8), (4, 0)
option 3: (0, 8)
option 4: (-4, 0)

Explanation:

Step1: Recall x-intercept definition

The x - intercept of a function \( y = f(x) \) is the point where \( y=f(x) = 0 \). In coordinate form, it is \( (x,0) \) where \( f(x)=0 \).

Step2: Find x-values where f(x)=0

Looking at the table:

• When \( x=- 4 \), \( f(x) = 0 \), so the point is \( (-4,0) \).
• When \( x = 4 \), \( f(x)=0 \), so the point is \( (4,0) \).
• For other values of \( x \) (like \( x=-2,0,2,6 \)), \( f(x)

eq0 \).

Answer:

\((-4, 0), (4, 0)\)