Question

the table below shows the genotypes that result in four different blood types in humans.genotype | blood type$i^a i^a$, $i^a i$ | a$i^b i^b$, $i^b i$ | b$i^a i^b$ | ab$ii$ | obased on the information in the table, which of the following describes alleles $i^a$ and $i^b$?○ the $i^a$ and $i^b$ alleles show sex linkage.○ the $i^a$ allele is recessive to the $i^b$ allele.○ the $i^a$ allele is dominant to the $i^b$ allele.○ the $i^a$ and $i^b$ alleles show codominance.

Explanation:

When an individual has the $I^A I^B$ genotype, their blood type is AB, meaning both the A and B traits are fully expressed rather than one masking the other. This pattern is codominance, where neither allele is dominant or recessive to the other. Sex linkage refers to genes on sex chromosomes, which is not relevant here. The other options incorrectly claim dominance or recessiveness between the alleles, which does not match the observed AB blood type from the $I^A I^B$ genotype.

Answer:

The $I^A$ and $I^B$ alleles show codominance.