Question

the table shows the coordinates of the vertices of $\triangle jkl$ and $\triangle jkl$ as follows: $\triangle jkl$ has vertices $j(-3,0)$, $k(0,4)$, $l(2,3)$ and $\triangle jkl$ has vertices $j(-3,-4)$, $k(0,0)$, $l(2,-1)$. which translation maps $\triangle jkl$ onto its image? options: 4 units down, 4 units up, 4 units to the right, 4 units to the left

Explanation:

Step1: Compare x-coordinates

For $J(-3,0)$ and $J'(-3,-4)$: $-3 = -3$
For $K(0,4)$ and $K'(0,0)$: $0 = 0$
For $L(2,3)$ and $L'(2,-1)$: $2 = 2$

Step2: Compare y-coordinates

For $J(-3,0)$ and $J'(-3,-4)$: $0 - 4 = -4$
For $K(0,4)$ and $K'(0,0)$: $4 - 4 = 0$
For $L(2,3)$ and $L'(2,-1)$: $3 - 4 = -1$

Step3: Identify translation

All x-coordinates stay same; y-coordinates decrease by 4.

Answer:

4 units down