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t tenth. 2) find the value of x. the right triangle has one leg of leng…

Question

t tenth.
2)
find the value of x. the right triangle has one leg of length 15, an acute angle of 67°, and the other leg is x.

Explanation:

Step1: Identify trigonometric ratio

We have a right triangle, with the side opposite the 67° angle as $x$, and the side adjacent to the 67° angle as 15. Use tangent: $\tan(\theta)=\frac{\text{opposite}}{\text{adjacent}}$

Step2: Substitute known values

$\tan(67^\circ)=\frac{x}{15}$

Step3: Solve for $x$

Rearrange to isolate $x$: $x=15\times\tan(67^\circ)$
Calculate $\tan(67^\circ)\approx2.3559$, so $x\approx15\times2.3559$

Step4: Compute final value

$x\approx35.3385$
Round to the nearest tenth: $x\approx35.3$

Answer:

$35.3$