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Question
there is a coordinate plane with a line graphed. the x - axis ranges from -5 to 5, and the y - axis ranges from -4 to 4. the line passes through (0, 2) and (4, 1) (or other points that can be inferred from the grid).
Assuming the problem is to find the equation of the line, here's the solution:
Step1: Identify two points
From the graph, two points on the line are \((0, 2)\) (y-intercept) and \((4, 1)\) (or we can also use \((-5, 3)\) and \((0, 2)\), let's use \((0, 2)\) and \((4, 1)\) for simplicity).
Step2: Calculate the slope (\(m\))
The slope formula is \(m=\frac{y_2 - y_1}{x_2 - x_1}\). Using \((x_1,y_1)=(0, 2)\) and \((x_2,y_2)=(4, 1)\), we get \(m=\frac{1 - 2}{4 - 0}=\frac{-1}{4}=-\frac{1}{4}\).
Step3: Use slope - intercept form (\(y = mx + b\))
The y - intercept (\(b\)) is 2 (from the point \((0, 2)\)). So the equation of the line is \(y=-\frac{1}{4}x + 2\).
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The equation of the line is \(y = -\frac{1}{4}x+2\) (If the problem was different, for example, finding slope, the slope is \(-\frac{1}{4}\); if finding y - intercept, it is 2. Since the problem was not specified, assuming finding the equation of the line, the answer is \(y = -\frac{1}{4}x + 2\))