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tor completely: $20x^{2}-32x - 2x^{3}$

Question

tor completely: $20x^{2}-32x - 2x^{3}$

Explanation:

Step1: Rearrange terms by degree

$-2x^3 + 20x^2 - 32x$

Step2: Factor out GCF $-2x$

$-2x(x^2 - 10x + 16)$

Step3: Factor quadratic trinomial

Find two numbers that multiply to $16$ and add to $-10$: $-2$ and $-8$.
$-2x(x - 2)(x - 8)$

Answer:

$-2x(x - 2)(x - 8)$