Question

triangle lmn has coordinates l(2,1), m(3,1), and n(1,6). the triangle is reflected across the x - axis. write the coordinates of △lmn.

Explanation:

Step1: Recall reflection rule

When reflecting a point $(x,y)$ across the $x - axis$, the rule is $(x,y)\to(x, - y)$.

Step2: Find coordinates of $L'$

For point $L(2,1)$, applying the rule: $L(2,1)\to L'(2,-1)$.

Step3: Find coordinates of $M'$

For point $M(3,1)$, applying the rule: $M(3,1)\to M'(3,-1)$.

Step4: Find coordinates of $N'$

For point $N(1,6)$, applying the rule: $N(1,6)\to N'(1,-6)$.

Answer:

$L'(2,-1), M'(3,-1), N'(1,-6)$