Question

two right triangles, △abd and △acd, were created from △abc by constructing ad ⊥ cb. follow these steps to prove that $\frac{sin(b)}{b}=\frac{sin(c)}{c}$. 1. for △abd, $sin(b)=\frac{h}{c}$. 2. multiply both sides of the equation by c and simplify. the equation $sin(b)=\frac{h}{c}$ becomes $csin(b)=h$. 3. for △acd, $sin(c)=\frac{h}{b}$. 4. multiply both sides of the equation by b and simplify. the equation $sin(c)=\frac{h}{b}$ becomes

Explanation:

Step1: Given $\sin(C)=\frac{h}{b}$

We want to isolate $h$.

Step2: Multiply both sides by $b$

$b\times\sin(C)=b\times\frac{h}{b}$

Step3: Simplify the right - hand side

$b\sin(C)=h$

Answer:

$b\sin(C)=h$