Question

two semicircles are attached to the sides of a rectangle as shown.
what is the area of this figure?
use 3.14 for pi.
enter your answer in the box. round only your final answer to the nearest whole number.
$ft^{2}$

Explanation:

Step1: Calculate area of rectangle

The rectangle has length $18$ ft and width $8$ ft. Area of rectangle is $\text{length} \times \text{width}$.
$\text{Area}_{\text{rectangle}} = 18 \times 8 = 144$ $\text{ft}^2$

Step2: Calculate area of two semicircles

Two semicircles with diameter $8$ ft form one full circle. Radius $r = \frac{8}{2} = 4$ ft. Area of circle is $\pi r^2$, use $\pi=3.14$.
$\text{Area}_{\text{circles}} = 3.14 \times 4^2 = 3.14 \times 16 = 50.24$ $\text{ft}^2$

Step3: Sum the two areas

Add the area of the rectangle and the area of the combined circle.
$\text{Total Area} = 144 + 50.24 = 194.24$

Step4: Round to nearest whole number

Round $194.24$ to the nearest whole number.
$194.24 \approx 194$

Answer:

194 $\text{ft}^2$