Question

unit review - right triangles and trigonometry
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solve for y.
$cos(23^{circ}) = sin(y)$
$y = ?^{circ}$
$sin(x) = cos(90^{circ}-x)$
$cos(x) = sin(90^{circ}-x)$
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Explanation:

Step1: Use co-function identity

Recall $\cos(x) = \sin(90^\circ - x)$

Step2: Substitute $x=23^\circ$

$\cos(23^\circ) = \sin(90^\circ - 23^\circ)$

Step3: Calculate the difference

$90^\circ - 23^\circ = 67^\circ$

Answer:

$67$