Question

use the figure below and the genetic code table to determine the identity of the structure indicated by z, x, u, o. n terminus-gly-glu-his-ser-c terminus n terminus-pro-leu-val-ser-c terminus c terminus-gly-glu-his-ser-n terminus c terminus-pro-leu-val-ser-n terminus

Explanation:

Step1: Identify the process

This is a translation process where mRNA codons are used to form an amino - acid sequence. The ribosome reads the mRNA in the 5' to 3' direction.

Step2: Match codons to amino - acids

The codons GUG codes for Valine (Val), AGU codes for Serine (Ser), and CGA codes for Arginine (Arg). But looking at the options, we assume the relevant part of the sequence is being considered. The start of translation gives the N - terminus and the end gives the C - terminus. Reading the mRNA from 5' to 3' and using the genetic code table, we get an amino - acid sequence starting with the N - terminus.

Step3: Analyze options

The correct amino - acid sequence should have the N - terminus at the start. The sequence that follows the translation rules and has the correct orientation is [N terminus]-Pro - Leu - Val - Ser-[C terminus]. Proline (Pro) would come from an appropriate codon in the mRNA sequence before the ones shown in the key part of the image, but based on the general concept of translation direction and amino - acid formation, this is the correct option.

Answer:

[N terminus]-Pro - Leu - Val - Ser-[C terminus]