QUESTION IMAGE
Question
use the given information to complete the proof of the following theorem.
if opposite sides of a quadrilateral are congruent, then it is a parallelogram.
by definition, a parallelogram is a quadrilateral in which both pairs of opposite sides are parallel.
use this definition in your proof.
given: $overline{ab} \cong \overline{cd}$
$overline{ad} \cong \overline{bc}$
prove: $abcd$ is a parallelogram
statement reason
1 $overline{ab} \cong \overline{cd}$ given
2 $overline{ad} \cong \overline{bc}$ given
3 $\overline{\square} \cong \overline{\square}$ reason?
4 $\triangle abd \cong \triangle \square$ reason?
5 $\angle 1 \cong \angle \square$ reason?
6 $\angle 2 \cong \angle \square$ reason?
7 $overline{ab} \parallel \overline{\square}$ if alt. int. $\angle$s $\cong$, then lines $\parallel$
8 $overline{ad} \parallel \overline{\square}$ if alt. int. $\angle$s $\cong$, then lines $\parallel$
9 $abcd$ is a parallelogram reason?
Step 1: Identify the common side
In triangles \( \triangle ABD \) and \( \triangle CDB \), the side \( \overline{BD} \) is common to both triangles. So, \( \overline{BD} \cong \overline{BD} \) by the Reflexive Property of Congruence.
Step 2: Prove triangle congruence
We have \( \overline{AB} \cong \overline{CD} \) (given), \( \overline{AD} \cong \overline{BC} \) (given), and \( \overline{BD} \cong \overline{BD} \) (reflexive). By the SSS (Side - Side - Side) Congruence Postulate, \( \triangle ABD \cong \triangle CDB \).
Step 3: Corresponding angles congruence
Since \( \triangle ABD \cong \triangle CDB \), their corresponding angles are congruent. So, \( \angle 1\cong\angle 3 \) and \( \angle 2\cong\angle 4 \) (Corresponding Parts of Congruent Triangles are Congruent - CPCTC).
Step 4: Prove sides are parallel
- For \( \overline{AB} \parallel \overline{CD} \): \( \angle 1 \) and \( \angle 3 \) are alternate interior angles. Since \( \angle 1\cong\angle 3 \), by the Alternate Interior Angles Theorem, \( \overline{AB} \parallel \overline{CD} \).
- For \( \overline{AD} \parallel \overline{BC} \): \( \angle 2 \) and \( \angle 4 \) are alternate interior angles. Since \( \angle 2\cong\angle 4 \), by the Alternate Interior Angles Theorem, \( \overline{AD} \parallel \overline{BC} \).
Step 5: Conclude it's a parallelogram
Since both pairs of opposite sides (\( \overline{AB} \parallel \overline{CD} \) and \( \overline{AD} \parallel \overline{BC} \)) of quadrilateral \( ABCD \) are parallel, by the definition of a parallelogram, \( ABCD \) is a parallelogram.
Now, filling in the table:
Statement 3:
\( \overline{BD} \cong \overline{BD} \)
Reason: Reflexive Property of Congruence
Statement 4:
\( \triangle ABD \cong \triangle CDB \)
Reason: SSS Congruence Postulate
Statement 5:
\( \angle 1\cong\angle 3 \)
Reason: CPCTC (Corresponding Parts of Congruent Triangles are Congruent)
Statement 6:
\( \angle 2\cong\angle 4 \)
Reason: CPCTC (Corresponding Parts of Congruent Triangles are Congruent)
Statement 7:
\( \overline{AB} \parallel \overline{CD} \)
Reason: If alternate interior angles are congruent, then lines are parallel (Alternate Interior Angles Theorem)
Statement 8:
\( \overline{AD} \parallel \overline{BC} \)
Reason: If alternate interior angles are congruent, then lines are parallel (Alternate Interior Angles Theorem)
Statement 9:
\( ABCD \) is a parallelogram
Reason: Definition of a parallelogram (both pairs of opposite sides are parallel)
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- \( \boldsymbol{\overline{BD} \cong \overline{BD}} \); Reason: Reflexive Property of Congruence
- \( \boldsymbol{\triangle ABD \cong \triangle CDB} \); Reason: SSS Congruence Postulate
- \( \boldsymbol{\angle 1\cong\angle 3} \); Reason: CPCTC
- \( \boldsymbol{\angle 2\cong\angle 4} \); Reason: CPCTC
- \( \boldsymbol{\overline{AB} \parallel \overline{CD}} \); Reason: Alternate Interior Angles Theorem
- \( \boldsymbol{\overline{AD} \parallel \overline{BC}} \); Reason: Alternate Interior Angles Theorem
- \( \boldsymbol{ABCD} \) is a parallelogram; Reason: Definition of a parallelogram