Question

use the graph to estimate the average rate of change of the percentage of new employees from 1994 to 2000, from 2000 to 2006, and from 1994 to 2006. what is the average rate of change of the percentage of new employees from 1994 to 2000? % per year (type an integer or a decimal rounded to two decimal places as needed.)

Explanation:

Step1: Identify values from graph

From the graph, in 1994 (let's assume year 1994 is \( x_1 = 1994 \)) the percentage \( y_1 \approx 0 \) (since it starts near 0). In 2000 (\( x_2 = 2000 \)), the percentage \( y_2 \approx 18 \) (estimating from the graph's peak around 2000).

Step2: Apply average rate of change formula

The formula for average rate of change is \( \frac{y_2 - y_1}{x_2 - x_1} \).
Substitute \( y_1 = 0 \), \( y_2 = 18 \), \( x_1 = 1994 \), \( x_2 = 2000 \).
\( \frac{18 - 0}{2000 - 1994} = \frac{18}{6} = 3 \). Wait, but maybe my estimation of \( y_2 \) is off? Wait, looking again, maybe in 1994 it's 0, in 2000 it's around 18? Wait, no, maybe the y-axis: let's check the grid. Each grid line: from 0 to 10 is 5 units? Wait, no, the y-axis has 0,5,10,15,20,25,30. So in 1994 (year 94 on x-axis), the percentage is around 0. In 2000 (year 00), it's around 18? Wait, no, maybe 1994 is year 0 (1994), 2000 is year 6 (2000 - 1994 = 6 years). Wait, the x-axis labels: 96, 98, 00, 02, 04, 06. So 1994 is before 96, maybe at x=94 (1994), y=0. At x=00 (2000), y=18? Wait, no, maybe the peak at 2000 is around 18? Wait, but let's recalculate. If in 1994, y=0; 2000, y=18. Then time difference is 6 years. So average rate is (18 - 0)/6 = 3. But maybe the graph is different. Wait, maybe in 1994, it's 0, in 2000, it's 18? Wait, no, maybe the correct estimation: let's see, in 1994, the percentage is 0 (starts at 0). In 2000, it's 18. So 18/6 = 3. But maybe the actual graph: let's check the x-axis: 1994 to 2000 is 6 years. If the y-value in 1994 is 0, and in 2000 is 18, then average rate is 3. But maybe I made a mistake. Wait, maybe the y-value in 2000 is 18? Let's confirm. The graph: at year 00 (2000), the peak is around 18 (between 15 and 20). So 18 - 0 = 18, over 6 years: 18/6 = 3.00.

Answer:

\( 3.00 \) (assuming the graph's values are as estimated; if the estimation is different, adjust accordingly. But based on the graph, this is the calculation.)