Question

use the partial - quotients method to find 673÷19. fill in the missing numbers.

Explanation:

Step1: Estimate first partial - quotient

We know that \(19\times10 = 190\). To find how many 190s are in 673, we start with \(673\div190\approx3\). So the first number we subtract is \(190\) which is \(10\times19\).

Step2: Calculate the first remainder

\(673-190 = 483\).

Step3: Subtract another 190

We subtract another \(190\) (i.e., \(10\times19\)) from \(483\). \(483 - 190=293\).

Step4: Subtract a third 190

We subtract another \(190\) (i.e., \(10\times19\)) from \(293\). \(293-190 = 103\).

Step5: Subtract 95

We know that \(95=5\times19\). \(103 - 95=8\).

Step6: Calculate the quotient

The quotient is \(10 + 10+10 + 5=35\) and the remainder is \(8\).

The long - division fill - in:
First box above the long - division bar: \(35\) (quotient)
Second box above the long - division bar: \(8\) (remainder)
First box next to \(19\times19\): \(10\)
Second box next to \(19\times19\): \(10\)
Third box next to \(19\times19\): \(10\)
Fourth box next to \(19\times19\): \(5\)
The remainders in the long - division steps: \(483\), \(293\), \(103\)

Answer:

The quotient is \(35\) and the remainder is \(8\). The filled - in numbers are as described above.