Question

use possible symmetry to determine whether the graph is the graph of an even function, an odd function, or a function that is neither even nor odd the function is because the graph is syn even odd neither even nor odd

Explanation:

An even function's graph is symmetric about the y-axis. For every point $(x, y)$ on the graph, the point $(-x, y)$ must also lie on the graph. Looking at the given graph, the point $(-2, \frac{2}{3})$ and $(2, \frac{2}{3})$, along with $(0,2)$ on the y-axis, show the graph is mirrored across the y-axis, which matches the symmetry rule for even functions.

Answer:

The function is even because the graph is symmetric about the y-axis.