Question

use the product property of logs to write as a sum of logarithms. simplify if possible. $log_{8}(64wa)$
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Explanation:

Step1: Apply product rule of logs

$\log_{8}(64wa) = \log_{8}(64) + \log_{8}(w) + \log_{8}(a)$

Step2: Simplify $\log_{8}(64)$

Since $8^2=64$, $\log_{8}(64)=2$

Answer:

$2 + \log_{8}(w) + \log_{8}(a)$