Question

use substitution to solve the system
\\( y = 2x + 10 )
\\( 3x - 5y = -20 )
\\( x = \square
\\( y = \square

Explanation:

Step1: Substitute $y$ into second equation

$3x - 3(2x + 10) = -27$

Step2: Simplify the equation

$3x - 6x - 30 = -27$

Step3: Combine like terms

$-3x - 30 = -27$

Step4: Isolate $x$ term

$-3x = -27 + 30$
$-3x = 3$

Step5: Solve for $x$

$x = \frac{3}{-3} = 1$

Step6: Solve for $y$ using $x=1$

$y = 2(1) + 10 = 12$

Answer:

$x = 1$, $y = 12$