Question

using hardy - weinberg to calculate heterozygous individuals. in a species of rodent, white coat color is recessive to the dominant brown color. in a population of 100 individuals, 16 are white and 84 are brown. of the 84 brown ones, how many are expected to be heterozygous (2pq)? multiple choice

Explanation:

Step1: Calculate frequency of recessive allele (q²)

The frequency of white - coated individuals (q²) is $\frac{16}{100}=0.16$.

Step2: Calculate q

Since $q^{2}=0.16$, then $q = \sqrt{0.16}=0.4$.

Step3: Calculate p

Using $p + q=1$, so $p=1 - q=1 - 0.4 = 0.6$.

Step4: Calculate frequency of heterozygotes (2pq)

$2pq=2\times0.6\times0.4 = 0.48$.

Step5: Calculate number of heterozygous individuals

Number of heterozygous individuals in population of 100 is $0.48\times100 = 48$.

Answer:

48