QUESTION IMAGE
Question
- what does absolute value mean?
please make a function table and graph for the following functions. use graph paper.
- f(x) = 4|x|
- f(x) = -3|x|
- f(x) = |x| - 2
graph the following piecewise function. use graph paper.
f(x) = x - 2, x ≤ 1
-2x + 3, x > 1
Brief Explanations
- The absolute value of a real number is its non-negative distance from zero on the number line, regardless of direction.
- For each absolute value function, generate input values (positive, negative, zero) to calculate corresponding output values, then plot the points. For the piecewise function, evaluate each sub-function over its defined domain, plot the segments, and note the endpoint behavior (closed/open circles).
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- The absolute value of a number, denoted as $|x|$, is the non-negative value of $x$ without regard to its sign. Mathematically, $|x| =
$$\begin{cases}
x & \text{if } x \geq 0 \\
-x & \text{if } x < 0
\end{cases}$$
$. It represents the distance of the number from 0 on the number line.
- ### Function Table for $f(x)=4|x|$:
| $x$ | $f(x)=4 | x | $ |
|---|---|---|---|
| -1 | $4 | -1 | =4$ |
| 0 | $4 | 0 | =0$ |
| 1 | $4 | 1 | =4$ |
| 2 | $4 | 2 | =8$ |
Graph: V-shaped with vertex at (0,0), opening upward, steeper than $|x|$ (slope $\pm4$).
- ### Function Table for $f(x)=-3|x|$:
| $x$ | $f(x)=-3 | x | $ |
|---|---|---|---|
| -1 | $-3 | -1 | =-3$ |
| 0 | $-3 | 0 | =0$ |
| 1 | $-3 | 1 | =-3$ |
| 2 | $-3 | 2 | =-6$ |
Graph: V-shaped with vertex at (0,0), opening downward, slope $\pm(-3)$.
- ### Function Table for $f(x)=|x|-2$:
| $x$ | $f(x)= | x | -2$ |
|---|---|---|---|
| -1 | $ | -1 | -2=-1$ |
| 0 | $ | 0 | -2=-2$ |
| 1 | $ | 1 | -2=-1$ |
| 2 | $ | 2 | -2=0$ |
Graph: V-shaped with vertex at (0,-2), opening upward, slope $\pm1$.
- ### Function Table for piecewise $f(x)=
$$\begin{cases}x-2, & x\leq1 \\ -2x+3, & x>1\end{cases}$$
$:
| $x$ | $f(x)$ |
|---|---|
| 0 | $0-2=-2$ |
| 1 | $1-2=-1$ (closed circle) |
| 2 | $-2(2)+3=-1$ |
| 3 | $-2(3)+3=-3$ |
Graph:
- For $x\leq1$: Line with slope 1, y-intercept -2, ending at closed circle (1,-1).
- For $x>1$: Line with slope -2, passing through (2,-1) (open circle at (1,1) since $-2(1)+3=1$, not included), extending downward to the right.