Question

what is the area of parallelogram abcd? 14 square units 16 square units 15 square units 13 square units

Explanation:

Step1: Identify coordinates of vertices

A(3,6), B(6,5), C(5,1), D(2,2)

Step2: Apply shoelace formula

Area = $\frac{1}{2}|(3×5 + 6×1 + 5×2 + 2×6) - (6×6 + 5×5 + 1×2 + 2×3)|$

Step3: Calculate sums

Sum1 = 15 + 6 + 10 + 12 = 43; Sum2 = 36 + 25 + 2 + 6 = 69

Step4: Compute area

Area = $\frac{1}{2}|43 - 69| = \frac{26}{2} = 13$

Answer:

13 square units