Question

what are the coordinates of m, the mid - point for pq, for p(-12,6) and q(1, - 8)
a (-\frac{18}{2},\frac{9}{2})
b (-\frac{13}{2},\frac{14}{2})
c (-\frac{11}{2},-1)
d (-\frac{6}{2},-\frac{7}{2})

Explanation:

Step1: Recall mid - point formula

The mid - point formula for two points $(x_1,y_1)$ and $(x_2,y_2)$ is $(\frac{x_1 + x_2}{2},\frac{y_1 + y_2}{2})$. Here, $x_1=-12,y_1 = 6,x_2 = 1,y_2=-8$.

Step2: Calculate the x - coordinate of the mid - point

$x=\frac{-12 + 1}{2}=\frac{-11}{2}$

Step3: Calculate the y - coordinate of the mid - point

$y=\frac{6+( - 8)}{2}=\frac{6 - 8}{2}=\frac{-2}{2}=-1$

Answer:

C. $(-\frac{11}{2},-1)$