Question

what is a correct first step in solving the inequality $-4(3 - 5x) geq -6x + 9$?
$\circ$ $-12 - 20x \leq -6x + 9$
$\circ$ $-12 - 20x \geq -6x + 9$
$\circ$ $-12 + 20x \leq -6x + 9$
$\circ$ $-12 + 20x \geq -6x + 9$

Explanation:

Step1: Apply distributive property

$-4(3 - 5x) = (-4)\times3 + (-4)\times(-5x) = -12 + 20x$

Step2: Keep inequality sign unchanged

Since we are only expanding (not multiplying/dividing by a negative number), the $\geq$ sign stays the same.

Answer:

-12 + 20x ≥ -6x + 9