Question

what is the factorization of the expression below? 9x^2 - 4y^2 a. (3x - 2y)(3x - 2y) b. (9x - 2y)(x - 2y) c. (9x - 2y)(x + 2y) d. (3x - 2y)(3x + 2y)

Explanation:

Step1: Recall difference - of - squares formula

The difference - of - squares formula is $a^{2}-b^{2}=(a - b)(a + b)$.

Step2: Rewrite the given expression

We can rewrite $9x^{2}-4y^{2}$ as $(3x)^{2}-(2y)^{2}$, where $a = 3x$ and $b=2y$.

Step3: Apply the formula

Using the difference - of - squares formula, $(3x)^{2}-(2y)^{2}=(3x - 2y)(3x + 2y)$.

Answer:

D. $(3x - 2y)(3x + 2y)$