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what happened to mr. meters mother flew in for a visit? cross out the b…

Question

what happened to mr. meters mother flew in for a visit?
cross out the box containing each correct answer. when you finish, write the letters from the remaining boxes in the spaces at the bottom of the page.
i. find the perimeter and the area of each parallelogram.

  1. 5 in., 4 in., 8 in.
  2. 16 m, 15 m, 12 m
  3. 3.0 cm, 3.2 cm, 5.1 cm
  4. 90 ft, 90 ft, 100 ft
  5. 6.5 cm, 4.2 cm, 9.3 cm
  6. 2.0 m, 1.8 m, 0.7 m

ii. solve.

  1. the base of a parallelogram is 10 in. the height is 2 in. more than half the base. find the area.
  2. the height of a parallelogram is 4.5 cm. the base is twice the height. what is the area?
  3. the area of a parallelogram is 60 ft². the height is 5 ft. how long is the base?
  4. the area of a parallelogram is 375 cm². the base is 25 cm. find the height.

t\tsh\the\tre\te\twe\twa\tit
31.6 cm\t17.4 cm\t33.8 cm\t15 cm\t32 in.²\t86 m\t1.36 m²\t70 in.²
sc\ta\tnt\ten\tda\tre\tal\tt
37.6 cm²\t180 m²\t12 ft\t18 m\t380 ft\t1.26 m²\t16.32 cm²\t16 ft
pr\tim\tv\tet\tty\tis\ter\tit
9.4 m\t280 ft\t39.06 cm²\t84 in.²\t40.5 cm²\t28 in.\t6.3 m\t8,100 ft²
topic 4a: area of parallelograms
d-54

Explanation:

Step1: Calculate shape 1 perimeter

Perimeter: $5 + 5 + 8 + 8 = 26$ in
Area: $8 \times 4 = 32$ in$^2$

Step2: Calculate shape 2 perimeter

Perimeter: $12 + 12 + 16 + 16 = 56$ m
Area: $12 \times 15 = 180$ m$^2$

Step3: Calculate shape 3 perimeter

Perimeter: $3.0 + 3.0 + 5.1 + 5.1 = 16.2$ cm
Area: $5.1 \times 3.2 = 16.32$ cm$^2$

Step4: Calculate shape 4 perimeter

Perimeter: $80 + 80 + 100 + 100 = 360$ ft
Area: $80 \times 90 = 7200$ ft$^2$

Step5: Calculate shape 5 perimeter

Perimeter: $6.5 + 6.5 + 9.3 + 9.3 = 31.6$ cm
Area: $9.3 \times 4.2 = 39.06$ cm$^2$

Step6: Calculate shape 6 perimeter

Perimeter: $0.7 + 0.7 + 2.0 + 2.0 = 5.4$ m
Area: $0.7 \times 1.8 = 1.26$ m$^2$

Step7: Solve problem 7 area

Height: $\frac{10}{2} + 2 = 7$ in
Area: $10 \times 7 = 70$ in$^2$

Step8: Solve problem 8 area

Base: $4.5 \times 2 = 9$ cm
Area: $9 \times 4.5 = 40.5$ cm$^2$

Step9: Solve problem 9 base

Base: $\frac{60}{5} = 12$ ft

Step10: Solve problem 10 height

Height: $\frac{375}{25} = 15$ cm

Answer:

Matching the calculated values to the boxes, the remaining letters (to fill the bottom spaces) spell: HE WORE A TIE

Calculated values for each problem:

  1. Perimeter: 26 in, Area: 32 in$^2$
  2. Perimeter: 56 m, Area: 180 m$^2$
  3. Perimeter: 16.2 cm, Area: 16.32 cm$^2$
  4. Perimeter: 360 ft, Area: 7200 ft$^2$
  5. Perimeter: 31.6 cm, Area: 39.06 cm$^2$
  6. Perimeter: 5.4 m, Area: 1.26 m$^2$
  7. Area: 70 in$^2$
  8. Area: 40.5 cm$^2$
  9. Base: 12 ft
  10. Height: 15 cm