Question

what is the length of the hypotenuse of the triangle when x = 2?
the length of the hypotenuse is \\(\square\\) unit(s).
(type an integer or decimal rounded to the nearest tenth as needed.)

Explanation:

Step1: Calculate leg lengths at x=2

First leg: $3(2)+6=12$
Second leg: $6(2)-7=5$

Step2: Apply Pythagorean theorem

Let $c$ = hypotenuse. Formula: $c=\sqrt{a^2+b^2}$
$\sqrt{12^2+5^2}=\sqrt{144+25}=\sqrt{169}$

Step3: Simplify the square root

$\sqrt{169}=13$

Answer:

13