Question

1. what operation would you use to solve 10 = 6y? explain your reasoning.

Explanation:

Step1: Identify the equation type

The equation is \( 10 = 6y \) (assuming a typo, maybe \( 10 = 6y \) or \( 10 = 6 + y \), but likely \( 10 = 6y \) meaning 6 times y equals 10). To isolate y, we need to reverse the multiplication of 6 and y.

Step2: Choose the operation

The inverse operation of multiplication is division. So we divide both sides of the equation by 6. For the equation \( 10 = 6y \), dividing both sides by 6 gives \( y=\frac{10}{6}=\frac{5}{3} \). If the equation was \( 10 = 6 + y \) (maybe a typo in the original problem), the inverse of addition is subtraction, but given the form \( 6y \) (6 times y), division is the operation.

Answer:

To solve \( 10 = 6y \) (assuming the equation is "10 equals 6 times y"), we use division. The equation represents "6 multiplied by \( y \) equals 10". To isolate \( y \), we perform the inverse operation of multiplication, which is division. We divide both sides of the equation by 6: \( y=\frac{10}{6}=\frac{5}{3} \).

(Note: If the intended equation was \( 10 = 6 + y \) (a common typo for "6y"), the operation would be subtraction. But the form "6y" implies multiplication, so division is correct here.)