Question

what is the perimeter of $delta wxy$?

Explanation:

Step1: Identify coordinates

Points: $W(0,10)$, $X(0,-2)$, $Y(-10,10)$

Step2: Calculate length $WX$

Vertical line, subtract y-values:
$WX = |10 - (-2)| = 12$

Step3: Calculate length $WY$

Horizontal line, subtract x-values:
$WY = |0 - (-10)| = 10$

Step4: Calculate length $XY$

Use distance formula $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$:
$XY = \sqrt{(-10-0)^2+(10-(-2))^2} = \sqrt{(-10)^2+(12)^2} = \sqrt{100+144} = \sqrt{244} = 2\sqrt{61} \approx 15.62$

Step5: Sum sides for perimeter

Add all three side lengths:
$Perimeter = WX + WY + XY$

Answer:

$22 + 2\sqrt{61}$ (or approximately $37.62$)