Question

what is the product of \\(\frac{4f}{5g}\\) and \\(\frac{f}{g}\\) when \\(g \
eq 0\\)? \\(\frac{16}{25}\\) \\(\frac{4}{5}\\) \\(\frac{4f^2}{5g^2}\\) \\(\frac{16f^2}{25g^2}\\)

Explanation:

Step1: Multiply the two fractions

To find the product of \(\frac{4f}{5g}\) and \(\frac{f}{g}\), we multiply the numerators together and the denominators together. So, \(\frac{4f}{5g} \times \frac{f}{g}=\frac{4f\times f}{5g\times g}\).

Step2: Simplify the expression

Simplify the numerator and the denominator. For the numerator, \(f\times f = f^{2}\), and for the denominator, \(g\times g = g^{2}\). So the expression becomes \(\frac{4f^{2}}{5g^{2}}\).

Answer:

\(\frac{4f^{2}}{5g^{2}}\) (corresponding to the option \(\frac{4f^{2}}{5g^{2}}\))